求这个产分匹配的设计思路

simpson

SAW的Terminating load impedance: ZL = 150 Ω|| 82 nH (balanced)
这是SAW的

LNA的ZIN Required SAW impedance(parallel model)
f=881MHz 302|-0.67 Ω|pF   这是LAN的

现在求这个产分匹配的设计思路，谢谢了！

[em03]

simpson

【文件名】:10427@52RD_matching design epcos SAW tp SP6.doc
【格　式】:doc
【大　小】:180K
【简　介】:
【目　录】:

Epcos SAW  Terminating load impedance: ZL = 150 Ω|| 82 nH (balanced)
conversion to single ended equivalent  ZL = 75 Ω|| 41 nH
Draw this point on Smith(Z0=75) Point:67.66+j22.358
  

SP6 LNA Zin Required SAW impedance(parallel model) f=881MHz  Zin=302|-0.67 Ω|pF （ ‘|’ means Parallel？）
conversion to single ended equivalent Zin=151|-1.34 Ω|pF
Draw this point on Smith(Z0=75) Point:68-j74.7

Then need to converse 67.66+j22.358 to 68-j74.7

So, we just need to add a Series capacitance 1.9pF to the differential circuit.
详见附件。大家看看对否？

sewreo

mark一下，看看高手们怎么回答