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发表于 2006-2-14 11:23:00
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<P break-all; LINE-HEIGHT: 14pt"><FONT face=宋体>一个要求</FONT>OIP3 20dBm<FONT face=宋体>的</FONT> LNA ,<FONT face=宋体>在输入</FONT>-30dBm<FONT face=宋体>时</FONT>,Gain 12dB,<FONT face=宋体>公式</FONT>:OIP3=POUT+A/2 OIP3=20dBm; POUT=-18dBm <FONT face=宋体>得到</FONT>A=76dBc<p></p></P><P break-all; LINE-HEIGHT: 14pt"><FONT face=宋体>所以交调分量自然是</FONT>:-18-76=-94dBm<p></p></P><P 0cm 0cm 0pt; TEXT-INDENT: 21.25pt">对移动通信的<FONT face="Times New Roman">CDMA </FONT>信号而言,其<FONT face="Times New Roman">IM3</FONT>(即<FONT face="Times New Roman">ACPR</FONT>)与<FONT face="Times New Roman">IP3</FONT>的关系可以通过一公式表示。</P><P 0cm 0cm 0pt; TEXT-INDENT: 21.25pt"><p><FONT face="Times New Roman"> </FONT></p></P><P 0cm 0cm 0pt; TEXT-INDENT: 21.25pt; TEXT-ALIGN: center" align=center><FONT face="Times New Roman">IP3=-5log[P<SUB>IM3</SUB>(f<SUB>1</SUB>,f<SUB>2</SUB>)B<SUP>3</SUP>/P<SUB>O</SUB>[(3B-f<SUB>1</SUB>)<SUP>3</SUP>-(3B-f<SUB>2</SUB>)<SUP>3</SUP>]]+22.2 (dBm)</FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 21.25pt"><p><FONT face="Times New Roman"> </FONT></p></P><P 0cm 0cm 0pt"><FONT face="Times New Roman"> </FONT>其中:<FONT face="Times New Roman"> P<SUB>IM3</SUB>(f<SUB>1</SUB>,f<SUB>2</SUB>) </FONT>表示要求的<FONT face="Times New Roman">IM3</FONT>的输出功率(<FONT face="Times New Roman">W</FONT>)</P><P 0cm 0cm 0pt"><FONT face="Times New Roman"> B </FONT>表示二分之一<FONT face="Times New Roman">CDMA</FONT>信号带宽<FONT face="Times New Roman"> </FONT>(<FONT face="Times New Roman">KHz</FONT>)</P><P 0cm 0cm 0pt"><FONT face="Times New Roman"> f<SUB>1</SUB>,f<SUB>2</SUB></FONT>表示两个边带频率相对于中心频率的差值(<FONT face="Times New Roman">KHz</FONT>)</P><P 0cm 0cm 0pt"><FONT face="Times New Roman"> P<SUB>O</SUB> </FONT>表示输出功率(<FONT face="Times New Roman">W</FONT>)</P><P 0cm 0cm 0pt; tab-stops: 142.4pt"><p><FONT face="Times New Roman"> </FONT></p></P><P 0cm 0cm 0pt">设功放由两级组成,第一级<FONT face="Times New Roman">IM3</FONT>表示为<FONT face="Times New Roman">IM3D</FONT>,第二级<FONT face="Times New Roman">IM3</FONT>表示为<FONT face="Times New Roman">IM<st1:chmetcnv w:st="on" UnitName="F" SourceValue="3" HasSpace="False" Negative="False" NumberType="1" TCSC="0">3F</st1:chmetcnv></FONT>,则级联后的<FONT face="Times New Roman">IM3</FONT>表示为:</P><P 0cm 0cm 0pt; TEXT-INDENT: 21.25pt; TEXT-ALIGN: center" align=center><FONT face="Times New Roman">IM3=IM<st1:chmetcnv w:st="on" UnitName="F" SourceValue="3" HasSpace="False" Negative="False" NumberType="1" TCSC="0">3F</st1:chmetcnv> + 20log[1+10<SUP>(IM3D-IM<st1:chmetcnv w:st="on" UnitName="F" SourceValue="3" HasSpace="False" Negative="False" NumberType="1" TCSC="0">3F</st1:chmetcnv>/20)</SUP>]</FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 21.25pt; TEXT-ALIGN: center" align=center><p><FONT face="Times New Roman"> </FONT></p></P><P 0cm 0cm 0pt; tab-stops: 142.4pt"><FONT face="Times New Roman"> </FONT>多级放大器以次类推<p></p></P>[br]<p align=right><font color=red>+5 RD币</font></p> |
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