求知关于信道和对应频率的关系的小问题

cantona_ck

手机测试工作中的信道和频率的对应关系是什么我搞不太明白
虽然也许是个小问题,但是藏心里很有一段时间了,呵呵
希望高手指教

Scott

If we call Fl(n) the frequency value of the carrier ARFCN n in the lower band, and Fu(n) the corresponding frequency value in the upper band, we have:


P-GSM 900 Fl(n) = 890 + 0.2*n  1 <=  n <=  124  Fu(n) = Fl(n) + 45
E-GSM 900 Fl(n) = 890 + 0.2*n  0 <=  n <=  124  Fu(n) = Fl(n) + 45
                Fl(n) = 890 + 0.2*(n‑1024)  975 <=  n <=  1 023
R‑GSM 900 Fl(n) = 890 + 0.2*n  0 <= n <= 124  Fu(n) = Fl(n) + 45
                 Fl(n) = 890 + 0.2*(n‑1024)  955 <= n <= 1023   
DCS 1 800 Fl(n) = 1710.2 + 0.2*(n‑512)  512 <=  n <=  885  Fu(n) = Fl(n) + 95
PCS 1 900 FI(n) = 1850.2 + .2*(n-512)  512 <=  n <=  810  Fu(n) = FI(n) + 80
GSM 450 Fl(n) = 450.6 + 0.2*(n-259)  259 <= n <= 293  Fu(n) = Fl(n) + 10
GSM 480 Fl(n) = 479 + 0.2*(n-306)  306 <= n <= 340  Fu(n) = Fl(n) + 10
GSM 850 Fl(n) = 824.2 + 0.2*(n-128)  128 <= n <= 251  Fu(n) = Fl(n) + 45


Frequencies are in MHz.[br]<p align=right><font color=red>+3 RD币</font></p>

Scott

不能上表格，所以格式有点乱。可以直接去查GSM协议

angusxie

楼上回答真的不错！！！奖励一下！

cantona_ck

谢谢Scott