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发表于 2006-4-26 09:19:00
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<P>If the temperature of the two-port network is at 290°K, the source, two-port network, and
load are in thermal equilibrium. <FONT color=#ff0000>The noise power at the output is equivalent to the noise
power at the input and noise factor </FONT>becomes。</P><P>F = (Sin/Nin)/ (Sout/Nout) = (1/G)* (Nout/Nin); 因为Nin = Nout = BKT;</P><P>F = 1/G ; NF = 10*Log(1/G) = Loss(dB)</P><P>Because the two-port network noise figure is equal to its loss, equation (51) predicts that
adding a loss in front of a gain block degrades system noise figure dB for dB. Loss in
front of a gain stage gives a total noise figure for the cascaded pair equal to the gain
block’s noise figure plus the loss of the component added.<FONT color=#ff0000> The system noise figure is
optimized by avoiding or minimizing system losses. Added losses have less impact
behind gain stages</FONT>. (重温一遍,感觉书上这个地方的描述有误,最终的Loss还是正的,所以应该增加了NF系数)
SAW前后两边的噪声系数是一样的,唯一的不同是信号幅度降低了,信噪比变差了。</P><P><FONT color=#ff0000>所以最终的结果还是增加了NF系数,减低了系统的灵敏度! 多谢vlivli兄!</FONT></P> |
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