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发表于 2006-5-11 14:51:00
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<P 0cm 0cm 0pt 18pt; TEXT-INDENT: -18pt; mso-pagination: none; mso-list: l0 level1 lfo1; tab-stops: list 18.0pt">1. For a basic explanation of transforms, see the Microsoft Word document Transform.doc.<p></p></P><P 0cm 0cm 0pt 18pt; TEXT-INDENT: -18pt; mso-pagination: none; mso-list: l0 level1 lfo1; tab-stops: list 18.0pt">2. In this menu item, Norton’s transforms are used to modify the original resonator coupled filter structure to an electrically equivalent circuit. You can change the A and K parameters to get part values that are more desirable than those in the original circuit. This is in contrast to the Direct Coupled filters where the resulting circuit an approximation of the original. <p></p></P><P 0cm 0cm 0pt 18pt; TEXT-INDENT: -18pt; mso-pagination: none; mso-list: l0 level1 lfo1; tab-stops: list 18.0pt">3. <B>Note</B>: If R Load does not equal R Source, only two of the four circuit <B>Types</B> will generate a valid circuit. For example, if R Source = 50, R Load = 500, and a Butterworth response, only the Pi circuit types yield a result. <p></p></P><P 0cm 0cm 0pt 18pt; TEXT-INDENT: -18pt; mso-pagination: none; mso-list: l0 level1 lfo1; tab-stops: list 18.0pt">4. The bar graph represents ratios of part values. It is usually the case that the closer the various part values are to a 1:1 ratio, the easier the filter is to build. To achieve this, select a value of K that maximizes the bar heights. Then tweak K for part values that are readily obtainable.<p></p></P> |
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