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楼主 |
发表于 2009-6-28 16:29:43
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以下是引用yellowtoot在2009-6-25 23:24:58的发言:
实在是看不懂SC-FDMA是怎么实现的
请大侠帮解释一下啊,谢谢!
主要问题集中在,如何将图9中的I/Q经DFT就能变成图10中的频谱结构的[em04]
图10中用下面的话解释的
1,
The DFT sampling frequency is chosen such
that the time-domain waveform of one SC-FDMA symbol is fully represented by
M DFT bins spaced 15 kHz apart, with each bin representing one subcarrier in
which amplitude and phase are held constant for 66.7 µs
2,
A one-to-one correlation always exists between the number of data symbols to
be transmitted during one SC-FDMA symbol period and the number of DFT bins
created. This in turn becomes the number of occupied subcarriers. When an
意思大概为:
1, DFT的抽样频率选取, 恰好使各谱线之间的距离为15KHz
请问: 抽样频率可以任意选取吗? 从而使DFT的频率谱线间隔为任意值??
2, 符号的个数 与 DFT后的载波个数 相同, 且一一对应.
请教: 为什么会一一对应啊?
谢谢! |
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